Question

from the following triangle abc where ab=3 bc=4 and angle b is 90 o find sin a sec c cot a​

Answer 1

Step-by-step explanation:

sina =4/5

sec c= 5/4

cot a= 3/4

hence sina sec c cota = 4/5×5/4×3/4= 3/4

If you want any other information let me know

Answer 2

Answer:

See the attachment .

Step-by-step explanation: