Question

The displacement of a particle moving on a straight line is given by x=16t-2t^2. Distance travelled by the particle during the first 2 sec. is S1 and during first 6sec. is S2. Find 3S2/S1.

Answer 1

Hey Dear,

◆ Answer -

3S2/S1 = 3

◆ Explanation -

◆ Explanation -# Given -

x = 16t - 2t²

t1 = 2 s

t2 = 6 s

# Solution -

Displacement in first 2 s is given by -

S1 = 16t - 2t²

S1 = 16(2) - 2(2)²

S1 = 32 - 8

S1 = 24 m

Displacement in first 6 s is given by -

S2 = 16t - 2t²

S2 = 16(6) - 2(6)²

S2 = 96 - 72

S2 = 24 m

Therefore,

3S2/S1 = 3 × 24 / 24

3S2/S1 = 3

Hope this helped you.