If log100.5 = 1.6990, then number of zeros
that are between the decimal point and the
first significant figure in (0.5)100 is
А
28
B
29
c 30
D 31
Answers
Answered by
0
Step-by-step explanation:
ANSWER
Let N=(
6
1
)
200
Taking log both side on base 10.
logN=200log
6
1
=−200log6=−200(log2+log3)=−200(.301+.477)=155.6
Hence, number of required cyphers =155
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