Math, asked by lalithamedipalli123, 4 months ago

If log100.5 = 1.6990, then number of zeros
that are between the decimal point and the
first significant figure in (0.5)100 is
А
28
B
29
c 30
D 31​

Answers

Answered by realmeC1156789
0

Step-by-step explanation:

ANSWER

Let N=(

6

1

)

200

Taking log both side on base 10.

logN=200log

6

1

=−200log6=−200(log2+log3)=−200(.301+.477)=155.6

Hence, number of required cyphers =155

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