Question

From the foot of a 60m high tower the angle of elevation of a minor is 60 degree and from top of it is 30 degrees. Find the height of miner​

Answer 1

in △ADE

tan60 o = DE 60

⇒DE= 3

60 =20 3

and we can see that , BCDE is a rec\tan gle

so, BC=DE⇒BC=20 3

and BD=CE.......(1)

and in △ABC

tan30 o= 20 3

AB

⇒AB=20 3 × 31

=20

Now, as AD=AB+BD⇒60=20+BD⇒BD=40

and from (1)

BD=CE=40 (which is the height of the Building)

Therefore, Answer is 40

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