Question

(X-4)^2+5^2=13 solve the quadric equation plz plz plz plz plz plz

Answer 1

Step-by-step explanation:

-: (x−4) ^2+5 ^2 =13^ 2

Firstly let us expand the given equation,

⇒x^ 2 −8x+16++25=169

⇒x^ 2 −8x+41−169=0

⇒x^ 2 −8x−128=0

factorizing the expression,

⇒x^ 2 −16x+8x−128=0

⇒x(x−16)+8(x−1)=0

⇒(x+8)(x−16)=0

⇒(x+8)=0 or (x−16)=0

⇒x=−8 or x=16

∴ Value of x=−8,16

(ii) 3(x−2) ^2 =147

Firstly expand the given equation

⇒3(x^ 2 −4x+4)=147

⇒3x ^2 −12x+12=147

⇒3x^ 2 −12x+12−147=0

⇒3x ^2−12x−135=0

Dividing the equation by 3,

⇒x ^2−4x−45=0

factorizing the equation,

⇒x ^2 −9x+5x−45=0

⇒x(x−9)+5(x−9)=0

⇒(x+5)(x−9)=0

⇒(x+5)=0 or (x−9)=0

⇒x=−5 or x=9

∴ Value of x=−5,9