Question

From the given figure find :
1. sin A
2. cos C
3. tanA
4. cosec C
5. sec2A-tan2A​

Answer 1

Step-by-step explanation:

firstly AB = 5

AC = 13

and BC = 12 ( by pythagoras theorem)

thus, for angle A

P =12

h =13

b =5

1. sinA = p/h = 12/13

3. tanA = p/b = 12 /5

for angle C

p= 5

b=12

h =13

2. cosC = b/h = 12/13

4. cosecC = h/p = 13/5 ans