Question

from the given figure find the length of sides AB and BD​

Answer 1

Answer:

Step-by-step explanation:

In triangle ABC,

(AB)2=400+225

(AB)2=625

AB=25m

We assumed that AD=AC.

AD=20

IN TRIANGLE ABD..

(AD)2=625+(BD)2

400=625+(BD)2

400-625=(BD)2

225=(BD)2

BD=15..

therefore,ACBD is kite..

Answer 2

Given: A mixed shape with two right-angled triangles is present.

A Right angle $\triangle ABC$ using a pythagoras theorem,

$AB^2=BC^2+AC^2\\AB^2=20^2+15^2\\AB^2=400+225\\AB^2=625\\AB=25$

AB is the hypotenuse of another Right angle $\triangle ABC$,

According to the given figure length of every side of the given figure is different.

Other possibility is,

$AB^2=BD^2+AD^2\\25^2=7^2+24^2\\25^2=49+576\\625=625$

Therefore, AB = 25 and BD = 7