Question

From the given figure the length of hypotenuse AC and the perimeter of ABC​

Answer 1

Answer:

In ∆ABC, ∠B = 90° , and l(BC) = 21, and l(AB) = 20  ∴ According to Pythagoras’ theorem,  ∴ l(AC)2 = l(BC)2 + l(AB)2  ∴ l(AC)2 = 212 + 202  ∴ l(AC)2 = 441 + 400  ∴ l(AC)2 = 841  ∴ l(AC)2 = 292  ∴ l(AC) = 29  Perimeter of ∆ABC = l(AB) + l(BC) + l(AC)  = 20 + 21 + 29  = 70 ∴ The length of hypotenuse AC is 29 units, and the perimeter of ∆ABC is 70 units.Read more on Sarthaks.com - https://www.sarthaks.com/863375/from-the-given-figure-find-the-length-of-hypotenuse-ac-and-the-perimeter-of-abc

Answer 2

Answer:

hey here is ur answer

pls mark it as brainliest

Step-by-step explanation:

so as it is ryt angled triangle

use ptythagoras

ie (20) square+(21) square =(AC) square

=400+441

so ac=29 or -29

but negative sign is absurd because dimensions are never -ve

so ac ie hypotenuse =29 units.

and now perimeter =sum of length of all sides

so 20+21+29

ie 70 units