Question

From the given velocity-time graph find the
displacement of particle in duration from t=0 to t=5
sec.
(A) 40 m
(B) 50 m
(C) 35 m
(D) 75 m​

Answer 1

Explanation:

let v=s/t

s=v*t

area of v-t graph gives displacement

hence,

area of figure =trapezium

= 1/2 * height * sum of parallel sides

= 1/2* 10* 7

=35 m

Answer 2

Answer:

35m

Explanation: