From the given velocity-time graph find the
displacement of particle in duration from t=0 to t=5
sec.
(A) 40 m
(B) 50 m
(C) 35 m
(D) 75 m
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Answered by
5
Explanation:
let v=s/t
s=v*t
area of v-t graph gives displacement
hence,
area of figure =trapezium
= 1/2 * height * sum of parallel sides
= 1/2* 10* 7
=35 m
Answered by
0
Answer:
35m
Explanation:
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