Question

from the mixture of 4 moles Ca3(PO4)2 and moles of P4O10 and 6 moles of H3PO3 all the phosphorus atoms are removed then moles of P4 molecule formed from all the atoms is

Answer 1

Answer:

1.41 * 10-23 moles P4.

Explanation:

For the 1 mole of Ca3(PO2)2 and P4O10, we have 2 and 4 mole of P atoms respectively.  Hence, for the 4 moles of the Ca3(PO2)2 and 5 moles of P4O10 will have 4 * 2 = 8 mole and 5*4 = 20 mole of Phosphorus atoms respectively.  

Similarly, for the 6 mole of H3PO4, it will have 6 * 1 = 6 mole of Phosphorus atoms.

Therefore, the total moles of Phosphorus atoms present will be  = 8 + 20 + 6  = 34 Phosphorus atoms.

So, 34 P atoms will be present in the 34/4 = 8.5 Phosphorus(4P4) molecules.  

So, the moles of P4 will be = 8.5/6.023 * 10^23 = 1.41 * 10^-23 moles of P4.

Answer 2

Answer:

Explanation:For the 1 mole of Ca3(PO2)2 and P4O10, we have 2 and 4 mole of P atoms respectively.  Hence, for the 4 moles of the Ca3(PO2)2 and 5 moles of P4O10 will have 4 * 2 = 8 mole and 5*4 = 20 mole of Phosphorus atoms respectively.  

Similarly, for the 6 mole of H3PO4, it will have 6 * 1 = 6 mole of Phosphorus atoms.

Therefore, the total moles of Phosphorus atoms present will be  = 8 + 20 + 6  = 34 Phosphorus atoms.

So, 34 P atoms will be present in the 34/4 = 8.5 Phosphorus(4P4) molecules.  

So, the moles of P4 will be = 8.5/6.023 * 10^23 = 1.41 * 10^-23 moles of P4.