From the partial differential
equation by elimination
arbitrary constant from
Z=ax+by+a²+b²
a) qx + by+p+q
b) px+qy + p²+q²
c) p+q
d) px+qy
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Answer:
y2=Ax2+Bx+C
A,B and C are to be eliminated.
Differentiating,
2ydydx=2Ax+B
Again differentiating
2yd2ydx2+2(dydx)2=2A
Again differentiating
2yd3ydx3+2dydxd2ydx2+4dydxd2ydx2=0
yd3ydx3+3dydxd2ydx2=0
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