Question

from the quadratic equation whose one root is 4 + √3​

Answer 1

Answer:

ok

Step-by-step explanation:

Answer 2

Answer:

$x^{2} -8x +13$

Step-by-step explanation:

One root =4+ $\sqrt{3\\}$

one root = 4-$\sqrt{3}$

Quadratic equation is

$x^{2} -(sum)x + (product) =0\\x^{2} -[4 +\sqrt{3} + 4 - \sqrt{3}] + [(4 +\sqrt{3}) (4-\sqrt{3})]\\gives\\x^{2} -8x + 13$