Question

from the sum of 11a^3 - 3b^2 and 4a^3 + 6b^2 subtract the sum of 9a^3 + b^2 and 3a^3 - 4b^2​

Answer 1

Answer:

3a³+6b²

Step-by-step explanation:

First sum,

(11a³-3b²)+(4a³+6b²)= 15a³+3b²

Second sum,

(9a³+b²)+(3a³-4b²)= 12a³-3b²

Now, subtracting the first sum from the second sum,

(15a³+3b²)-(12a³-3b²)= 3a³+6b² (Answer)

Answer 2

Answer:

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