Question

from the sum of 13a+19b+12cand14a-21b+11c subtract the sum of 17a+13b-15c and 8a+12b-18c​

Answer 1

First set,

$\displaystyle\sf{(13a+19b+12c)+(14a-21b+11c)$

$=\displaystyle\sf{13a+19b+12c+14a-21b+11c$

$=\sf{27a-2b+23c$

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Second set,

$\sf{(17a+13b-15c)+(8a+12b-18c)$

$=\sf{17a+13b-15c+8a+12b-18c$

$=\sf{25a+25b-33c$

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First set - Second set,

$\sf{(27a-2b+23c)-(25a+25b-33c)$

$=\sf{27a-2b+23c-25a+25b-33c$

$=\sf{2a+23b-10c$

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$\boxed{\bold{\displaystyle\sf{Answer=2a+23b-10c}}}$