From the sum of 2p² - 3q2 + 4r² and p² + 2q² -3r² , Subtract 4p² + 2q² - 3r²
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Answer:
Subtracting (4p
2
q−3pq+5pq
2
−8p+7q−10) from (18−3p−11q+5pq−2pq
2
+5p
2
q)
we have,
= (18−3p−11q+5pq−2pq
2
+5p
2
q)−(4p
2
q−3pq+5pq
2
−8p+7q−10)
= 18−3p−11q+5pq−2pq
2
+5p
2
q−7p
2
q+3pq−5pq
2
+8p−7q+10
= 28+5p−78q+8pq−7pq
2
+p
2
q
Step-by-step explanation:
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