Question

From the sum of 2y^2+3yz,-y^2-yz-z^2 and yz+2z^2,subtract the sum of 3y^2-z^2 and -y^2+yz+z^2​

Answer 1

Answer:

- 3y^2+ 4yz + z^2

Step-by-step explanation:

=(2y^2+3yz+ -y^2-yz-z^2+ yz+2z^2 )-( 3y^2-z^2 + -y^2+yz+z^2 )

=> 2y^2+3yz-y^2-yz-z^2+ yz+2z^2 - 3y^2-z^2 -y^2+yz+z^2

=> 2y^2 -y^2 - 3y^2 -y^2 +3yz- yz+ yz + yz -z^2+ 2z^2 -z^2 + z^2

=>- 3y^2+ 4yz + z^2

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