Question

from the sum of 3x-y+11 and -y-11, subtract 3x-y-11

guys plz tell math answer of this Ncert question...

Answer 1

The required expression is -y+11.

Step-by-step explanation:

We need to find the sum of 3x-y+11 and -y-11, subtract 3x-y-11.

sum of 3x-y+11 and -y-11 is

$(3x-y+11)+(-y-11)$

$3x-y+11-y-11$

Combine like terms.

$3x+(-y-y)+(11-11)$

$3x-2y$

Now subtract 3x-y-11 from 3x-2y.

$3x-2y-(3x-y-11)$

$3x-2y-3x+y+11$

Combine like terms.

$(3x-3x)+(-2y+y)+11$

$-y+11$

Therefore, the required expression is -y+11.

#Learn more

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(2x + 5y)² + (2x - 5y)square​

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Answer 2

Answer:

(3x−y+11)+(−y−11)

3x-y+11-y-113x−y+11−y−11

Combine like terms.

3x+(-y-y)+(11-11)3x+(−y−y)+(11−11)

3x-2y3x−2y

Now subtract 3x-y-11 from 3x-2y.

3x-2y-(3x-y-11)3x−2y−(3x−y−11)

3x-2y-3x+y+113x−2y−3x+y+11

Combine like terms.

(3x-3x)+(-2y+y)+11(3x−3x)+(−2y+y)+11

-y+11−y+11

Therefore, the required expression is -y+11