Question

From the sum of (3x-y+z) and (-y-z), subtract (3x-y-2)​

Answer 1

Answer:

2

Step-by-step explanation:

3x-y+z + (-y-z) = 3x-y+z-y-z= 3x-2y

3x-2y=0

3x- y=2

(-) (+) (-)

-y=-2

therefore y=2

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