Question

From the sum of 4+ 3x and 5-4x +2x'2
subtract sum of 3x'2-5x and -x'2 + 2x+5
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Answer 1

Answer:

4 + 3x + 5 - 4x + 2x sq

= 4 + 5 + 3x - 4x + 2x sq

= 9 - x + 2x sq

= 2x sq - x + 9

3x sq - 5x + (- x sq + 2x + 5)

= 3x sq - 5x - x sq + 2x + 5

= 3x sq - x sq - 5x + 2x + 5

= 2x sq - 3x + 5

subtracting eq 2 from eq 1

2x sq - x + 9 - ( 2x sq - 3x + 5)

= 2x sq - X + 9 - 2x sq + 3x - 5

= 2x sq - 2x sq - x - 3x + 9 - 5

= - 4x + 4