Question

From the sum of (4 + 3x) and (5 ‒ 4x + 2x2), subtract the sum of (3x2 ‒ 5x) and (‒ x2 + 2x + 5).

Answer 1

Subtraction :-

$\tt(3 \times 2 - 5x) \: and \: ( - 2x + 2x + 5) \\ \tt \: = (6 - 5x) - ( - 2x + 2x + 5) \\ \tt \: = 6 - 5x \: \cancel{ + 2x} \cancel{ - 2x} - 5 \\ \tt = 6 - 5 - 5x = { \underline{ \boxed{ \bf{1 - 5x}}}}$

From the sum of :-

$\tt(4 + 3x) \: and \: (5 - 4x + 2 \times 2) \\ \tt = (4 + 3x) + (5 - 4x + 4) \\ \tt \: = 4 + 3x + 5 - 4x + 4 \\ \tt \: = 4 +5 + 4 + 3x - 4x \\ \tt ={ \underline{ \boxed{ \bf 13 - 1x}}}$