From the sum of 4+3z and 5-4x+2(x×x) subtract the sum of 3(x×x)-5x and (-x×x)+2x+5
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here your answer is
(4+3Z) +(5-4x+2×x)--(3(x×x)-5x)+(-x×x)+2x+5===== (4+3x+5-4x+2x^2) - (3x^2 - 5x-x^2 +2x+5)===
9-x+2x^2 +2x^2 +5x-2x-5
===4+2x
hope it helps you
mark as brainliest please
....
(4+3Z) +(5-4x+2×x)--(3(x×x)-5x)+(-x×x)+2x+5===== (4+3x+5-4x+2x^2) - (3x^2 - 5x-x^2 +2x+5)===
9-x+2x^2 +2x^2 +5x-2x-5
===4+2x
hope it helps you
mark as brainliest please
....
nainarawat2606:
Sorry to say but the answer is coming 4+2x
wait I will recheck it
now it's ok
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