From the sum of X² +3y² -6xy , 2x²-y²+8xy,y² +8 and x²-3xy subtract -3x² +4y²-xy +x-y +3
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Answer:
x²+3y²-6xy+2x²-y²+8xy+y²+8+x²-3xy
=x²+2x²+x²+3y²-y²+y²-6xy+8xy-3xy+8
=4x²+3y²-xy+8
substracting -3x²+4y²-xy+x-y+3
(4x²+3y²-xy+8)-(-3x²+4y²-xy+x-y+3 )
=4x²+3y²-xy+8+3x²-4y²+xy-x+y-3
=7x²-y²-x+y+5
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