Question

From the sum of x2 + 3y2 – 6xy, 2x2 - y2 + 8xy +
y2 + 8 and x2 - 4xy subtract the sum of –3x2 + 4y2
+ 3 and 4y2 - 5.​

Answer 1

Answer:

6x^2 -5y^2 +2xy +10

Step-by-step explanation:

x^2 + 3y^2 - 6xy + 2x^2 -y^2 +8xy +y^2 +8

= 3x^2 + 3y^2 + 2xy + 8

Now,

-3x^2 +4y^2 + 3 + 4y^2 - 5

= -3x^2 +8y^2 - 2

Therefore,

3x^2 +3y^2 +2xy + 8 - (-3x^2 +8y^2 -2)

= 3x^2 +3y^2 +2xy + 8 +3x^2 -8y^2 +2

= 6x^2 -5y^2 +2xy +10