From the sum of x2+3y2-6xy,2x2-y2+8xy,y2+8and x2-3xy subtract-3x2+4y2-xy+x-y+3
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Add x2 + 2xy + y2 to the sum of x2 − 3y2 and 2x2 − y2+ 9.
ANSWER:
Sum of x2 - 3y2 and 2x2 - y2 + 9
= (x2 - 3y2) + (2x2 - y2 + 9)
= x2 + 2x2 - 3y2 - y2+ 9
= 3x2 - 4y2 + 9
Now, required expression = (x2 + 2xy + y2) + (3x2 - 4y2 + 9)
= x2 + 3x2 + 2xy + y2 - 4y2 + 9
= 4x2 + 2xy - 3y2 + 9
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