from the sum of (x2+x+1) and (x2
-x+1) subtract (-x
2
-x+1)
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Answered by
4
x² + x + 1 + x² - x + 1
= 2x² + 2
2x² + 2 - (-x² - x + 1)
= 2x² + 2 + x² + x - 1
= 3x² + x + 1
Answered by
3
Answer:
(x² + x + 1) + (x² - x + 1) - (-x² - x + 1) = 3x² + x +1
Step-by-step explanation:
Let us consider,
sum of (x² + x + 1) & (x² - x + 1)
⇒ (x² + x + 1) + ( x² - x + 1)
⇒ 2x² + 2 + x - x
⇒ 2x² + 2
∴Sum of (x² + x + 1) & (x² - x + 1) = 2x² + 2 → (1)
And now, according to the given data,
From the sum of (x² + x + 1) & (x² - x + 1) subtract (-x² - x + 1)
⇒ (2x² + 2) - (-x² - x + 1) (∵ from eq.(1) )
⇒ 2x² + 2 + x² + x - 1
⇒ 3x² + x + 1
∴ (x² + x + 1) + (x² - x + 1) - (-x² - x + 1) = 3x² + x + 1
HOPE THIS WOULD BE HELPFUL FOR YOU
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