from the top foot of a 40m high tower,the angle of elevationof the top of a lighthouseare found to be 30°and 60°. find the height of a light house
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let BC be the height of the tower
AB be the height of the light house
and, D be the point from where there angles
are to be found
by question, in ∆BCD
tanD = BC/DC
tan30°= 40/DC
1/√3 = 40/DC
DC = 40√3 ...........(1)
Now in ∆ ABC
tanD=AC/DC
tan60°=AB+BC/DC
√3 =AB+40/40√
40√3x√3 =AB+40
40 x 3=AB+40
120=AB+40
AB=120-40
AB=80
Hence, the height of the light house is 80m.
AB be the height of the light house
and, D be the point from where there angles
are to be found
by question, in ∆BCD
tanD = BC/DC
tan30°= 40/DC
1/√3 = 40/DC
DC = 40√3 ...........(1)
Now in ∆ ABC
tanD=AC/DC
tan60°=AB+BC/DC
√3 =AB+40/40√
40√3x√3 =AB+40
40 x 3=AB+40
120=AB+40
AB=120-40
AB=80
Hence, the height of the light house is 80m.
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HÉŸ FŘÎÉŃĐ,
⚫♦▫your answer is in above attachment....
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HØPÉ ÎŤ HÉŁPŠ ŸØÚ
⚫♦▫your answer is in above attachment....
➖➖➖➖➖➖➖➖➖➖➖➖➖▫
HØPÉ ÎŤ HÉŁPŠ ŸØÚ
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