Question

From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower.
Army

Answer 1

Question:

From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower.

Answer:

7(√3+1) m.

Step-by-step explanation:

Let AB be the building of height 7 m and

EC be the height of tower.

A is the point from where elevation of

tower is 60° and the angle of depression

of its foot is 45°

EC = DE + CD

also, CD = AB = 7 m.

and BC = AD

A/q,

In right triangle ABC,

tan 45° = AB/BC

→ 1= 7/BC

BC = 7 m = AD

also,

In right triangle ADE,

tan 60° = DE/AD

V3 = DE/7

- DE = 7V3 m

Height of the tower = EC = DE + CD

=(7√3 +7) m = 7(√3+1) m.

Answer 2

Answer:

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