Question

from the top of a 7m high building the angle of elevation of the top of a cable Tower is 60 degree and the angle of the decoration of its foot is 45° determine the height of the tower

Answer 1

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Answer 2

AB be height of the building
AB=7m=DE
CD be the height of the tower
CD=CE+DE=CE+7
angle CAE=60°
angle ADB =angle EAD=45°

In triangle ABD, angle B=90°
tan45° = AB/BD
1=7/BD
7=BD
therefore,BD=AE=7m
In triangle ACE,angle E=90°
tan60°=CE/AE
√3=CE/7
CE=7√3m

Height of the tower=7√3+7
=7(√3+1)m
=7(1.73+1)
=7×2.73
=19.11m
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