From the top of a building 20m high, the angle of elevation of the top of a monument is 45degree and the angle of depression of its foot is 15 degree. Find the height of the monument.
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let AB be the building (with A at top) and CD be the monument (with C at top)
let AE║BD, AE = BD and AB = ED
In ΔAEC,
tan 45° = CE/ AE
⇒ CE = AE (tan 45° = 1) ................................ 1
alternate interior angles are equal
⇒ EAD = BDA = 45°
In ΔABD
tan 45° = AB/ BD
⇒ AB = BD (tan 45° = 1) ................................ 2
Since AE = BD
AB = CE (from 1 and 2)
thus the height of monument = CE + ED = CD = 20 + 20
= 40 m
Hope it helped
mark me as brainliest
let AE║BD, AE = BD and AB = ED
In ΔAEC,
tan 45° = CE/ AE
⇒ CE = AE (tan 45° = 1) ................................ 1
alternate interior angles are equal
⇒ EAD = BDA = 45°
In ΔABD
tan 45° = AB/ BD
⇒ AB = BD (tan 45° = 1) ................................ 2
Since AE = BD
AB = CE (from 1 and 2)
thus the height of monument = CE + ED = CD = 20 + 20
= 40 m
Hope it helped
mark me as brainliest
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Step-by-step explanation:
From the top of a building of 20m high the angle of elevation of the top of a monument is 45⁰ and the angle of depression of the foot of the monument is 30⁰. Find the height of the monument in nearest metre.
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