From the top of a building 60m high the angle of depression of the top and bottom of the tower are observed to be 30 degree and 60 degree. Find the height of the tower?
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Answer: 40m
Step-by-step explanation:refer your NCERT textbook pg no. 202 , example 6 for the drawing .
mark the first (smallest) triangle as ABE and second (largest) triangle as ADC
angle ABE & angle ADC are right angles .
In triangle ABE
tan60=60/AC
squareroot3 = 60/AC.
AC = 60/squareroot3 ---- 1
in triangle ADC
TAN30 =AB /EB ( EB = DC)
1/squareroot3 = AB / 60 / squareroot3
1 / AB = squareroot3 / 60 / squareroot3
THE squareroot3 BELOW 60 GETS MULTIPLIED BY THE squareroot3 ABOVE 60 .
1 / AB = 3 / 60
1 / AB = 1 / 20
AB = 20.
FROM FIGURE
AB + BC = AC
20m + BC = 60 m
BC = 40M.
ANS: THE HEIGHT OF THE TOWER ED IS 40m.
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