from the top of a building 69 m high the angle of elevation and depression of the top and the foot of another building are a and b respectively find the height of the second building
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Answer:
sushmitha
Secondary School Math 5 points
From the top of a building 60m high, the angle of depression of the top and bottom of a vertical lamp post are observed to be 30° and 60° respectively. Find the height of the lamp post and distance between the building and lamp post
Ask for details Follow Report by Gauravjain9327 15.02.2018
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parmesanchilliwack Ambitious
Answer:
The height of the lamp is 45 meters.
Step-by-step explanation:
Let the line segment AB represents the height of the lamp ( where A is the top of the lamp ), ED represents the height of the building,
While C is any point on ED such that CA ║ DB and CA = DB
Thus, by the below diagram,
In triangle ECA,
tan 30^{\circ}=\frac{EC}{CA}
\frac{1}{\sqrt{3}}=\frac{EC}{CA}\implies CA =\sqrt{3} EC
Now, in triangle EDB,
tan 60^{\circ}=\frac{ED}{DB}=\frac{60}{CA}
\implies \sqrt{3}CA = 60\implies CA = \frac{60}{\sqrt{3}}
Thus,
√3 EC = 60 / √3
⇒ 3 EC = 60 ⇒ EC = 20
Since, AB = CD = ED - EC = 60 - 20 = 40 meters,
Hence, the height of the lamp post is 40 meters.