Question

From the top of a building 7 m high the angle of
elevation of the top of a tower is 45° whereas the
angle of elevation of the top of tower to its foot is
60°. Find the height of tower.​

Answer 1

Step-by-step explanation:

Let AB be the building of height 7 m and EC be the height of tower.

A is the point from where elevation of tower is 60° and the angle of depression of its foot is 45°

EC = DE + CD

also, CD = AB = 7 m. and BC = AD A/q,

In right ΔABC, tan 45° = AB/BC ⇒ 1= 7/BC ⇒ BC = 7 m = AD

also, In right ΔADE, tan 60° = DE/AD ⇒ √3 = DE/7 ⇒ DE = 7√3 m

Height of the tower = EC = DE + CD = (7√3 + 7) m = 7(√3+1) m.

Answer 2

Step-by-step explanation:

answer is in the given pic. So,you can go and understand how the answer has been come