Question

From the top of a building 80 m high, a ball is thrown horizontally which hits the ground at a distance.The line joining the top of the building to the point where it hits the ground makes an angle of 45^(@) with the ground. Initial velocity of projection of the ball is (g=10 m//s^(2))

Answer 1

ANSWER

Time duration t for the ball to reach the ground = T=

2 h/g

t= 2*19.6/9.8 =2sec

horizontal distance traveled in 2 sec=19.6 given,as angle is 45

19.6sec = u*2sec

u=9.8sec

as the horizontal velocity component remains constant .