Math, asked by mannshah134, 9 months ago

from the top of a building an observer look at a car on the road and find the angle of depression 30 degree.if the height of the building is 45 metre, find how far is the car from building

Answers

Answered by TheValkyrie
5

Answer:

\bigstar{\bold{Distance\:=\:45\sqrt{3} \:m}}

Step-by-step explanation:

\Large{\underline{\underline{\it{Given:}}}}

  • Angle of depression = 30°
  • Height of the building = 45 m

\Large{\underline{\underline{\it{To\:Find:}}}}

  • The distance of car from the building

\Large{\underline{\underline{\it{Solution:}}}}

↠ From the given figure in the attatchment, AB= height of the building = 45 m, Angle C = 30°

↠ We need to find BC which is the distance from car to the building.

↠ tan C = opposite/ adjacent

    tan C = AB/ BC

    tan C = 45/BC

    tan 30° = 45/BC

     \dfrac{1}{\sqrt{3} } \:=\:\dfrac{45}{BC}

    BC = 45√3 m

\boxed{\bold{Distance\:=\:45\sqrt{3} \: m}}

\Large{\underline{\underline{\it{Notes:}}}}

↬ Sin A  = opposite/hypotenuse

↬ Cos A = adjacent/hypotenuse

↬ Tan A = opposite/ adjacent

Attachments:
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