Question

solve by elimination 2x+5y=4. 3x-2y+16=0



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Answer 1

Answer:

equations

2x-5y-4=0

3x-2y+16=0

by cross-multiplication

x/b1c2-b2c1 = y/c1a2-c2a1 = 1/a1b2-a2b1

x/-80-8 = y/-12-32 = 1/-4+15

x/-88 = y/-44 = 1/11

Therefore

1/11 = x/-88

x=-8

1/11=y/-44

y=-4

Step-by-step explanation:

please add as brilliant answer

Answer 2

Answer:

First choose an equation

2x = 5y + 4

x = 5y + 4/2

Then put the value of x in another equation

3x - 2y + 16 = 0

3(5y + 4/2) -2y + 16 = 0

15 y + 12/2 - 2y + 16 = 0

11y + 12 - 4y/2 + 16 = 0

11y + 12 /2 + 16 = 0

11y + 12/2 = -16

11y + 12 = -16*2

11y + 12 = -32

11y = -33 -12

11y = -44

y = -44/11

y = -4

Then put the value of y in another equation

x = 5y + 4/2

x = 5 * - 4+4/2

x = 16/2

x = -8

So, X = 8 and y = 4

Hope it's help you........