From the top of a hill, the angles of depression of two consecutive kilometre stones due east are found to be30°and45°. Find the distance of the two stones from the foot of the hill.
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Answered by
2
Answer:
Let the distance between the nearer kilometre stone and the hill be 'x' km.
So, the distance between the farther kilometre stone and the hill is '1+x' km since both are on the same side of the hill.
In triangle APB,
tan45
0
=
x
h
⇒1=
x
h
⇒h=x
In triangle AQB,
tan30
0
=
1+x
h
⇒
3
1
=
1+x
h
⇒1+x=
3
h
From equation 1,
1+h=
3
h⇒1=
3
h−h
⇒h=
3
−1
1
⇒h=1.365km
Hence option A is correct.
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Answer:
1.365 Km
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