From the top of a hill, the angles of depression of two consecutive kilometre stones due east are found to be 30°and 45°. Find the distance of the two stones from the foot of the hill.
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1
Answer:
Hence, the height of the hill is 1.365 km.
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Let the distance between the nearer kilometre stone and the hill be 'x' km.
So, the distance between the farther kilometre stone and the hill is '1+x' km since both are on the same side of the hill.
In triangle APB,
tan450=xh
⇒1=xh
⇒h=x
In triangle AQB,
tan300=1+xh
⇒31=1+xh
⇒1+x=3h
From equation 1,
1+h=3h⇒1=3h−h
⇒h=3−11
⇒h=1.365km
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