From the top of a light house an observer looking at a ship makes angle of depression of60°If the height of the light housr is 90 meter then find how far the ship is form light house (√3=1.73)
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angle of elevation= angle of depression
let dist of ship be x
tan 60= 90/x
√3= 90/X
X=90/√3
X=90√3/3
X= 30√3
ans dist of ship from the light house is 51.9m
let dist of ship be x
tan 60= 90/x
√3= 90/X
X=90/√3
X=90√3/3
X= 30√3
ans dist of ship from the light house is 51.9m
Answered by
3
Angle of depression = Angle of elevation
If you will draw the diagram as per question then your perpendicular height is 90m then according to Trigonometry Tan value of 60° = Perpendicular/Base then your calculations will be Tan 60° = 90/b then b= 90/tan 60° then apply value of tan 60° and Base(Distance of ship to lighthouse) = 52.02
If you will draw the diagram as per question then your perpendicular height is 90m then according to Trigonometry Tan value of 60° = Perpendicular/Base then your calculations will be Tan 60° = 90/b then b= 90/tan 60° then apply value of tan 60° and Base(Distance of ship to lighthouse) = 52.02
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