From the top of a lighthouse an observer looking at a ship makes angle of depression of 60°. If the height the lighthouse is 90 metre then find how far the ship is from the lighthouse. (root 3=1.73
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according to the attachment,
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tan∅ = AB/BC
tan60° = 90/BC
√3 = 90/BC
BC×√3 = 90
BC = 90/√3
BC. = 90/1.73
BC = 52.023 m (approximate)
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so ship 52.023 meter far from the light house.
_________________________
tan∅ = AB/BC
tan60° = 90/BC
√3 = 90/BC
BC×√3 = 90
BC = 90/√3
BC. = 90/1.73
BC = 52.023 m (approximate)
___________________________________
so ship 52.023 meter far from the light house.
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