Question

From the top of a minar 30 mts. high, the angles of depression of the top and bottom of a tower are 30° and 60° respectively. Find the height of the tower.​

Answer 1

Answer:

Height of tower = 20 meter

Step-by-step explanation:

Refer to the attachment

Answer 2

Answer:

20 m

Step-by-step explanation:

Let the height of tower be h m.

We have given height of minar is 30 m.

A.O.D. of the top and bottom of a tower are 30° and 60° respectively.

In figure : AC represents height of minar and AE = DB represents height of height of tower .

Now :

In Δ ABC

tan 60 = AB / 30

AB =  30 / √ 3 m  OR 10 √ 3

In Δ CDE

tan 30 = EC / DC

But DC = AB =  30 √ 3 m

1 / √ 3 = EC /  10 √ 3

EC = 10 m

Now we can replace by h as :

h = AC - EC  [ AC is nothing but minar's height ]

h = 30 - 10 m

h = 20 m

Hence , the  height of tower would be 20 m.