Question

From the top of a rock 50√3 m high, the angle of depression of a car on the ground is observed to be 30°. Find the distance of the car from the rock.​

Answer 1

Answer:

150 m

Step-by-step explanation:

The height of the rock = 50√3 m

Distance of the car from the bottom of rock be x (See figure)

$tan\ 30^o = \frac{50\sqrt3 }{x}$

$\frac{1}{\sqrt3}=\frac{50\sqrt3}{x} \ \ \ [\because tan\ 30^o=\frac{1}{\sqrt3}]$

$x=50\sqrt 3 \times \sqrt 3$

$x=50\times 3=150\ m$

Hence, distance of the car from bottom of the rock is 150 m.