Question

From the top of a tower 100 m high a man observes two car on the opposite side of the tower and in the straight line with its base with the angles of depression 30 degree and 45 degree find the distance between the cars

Answer 1

dist btwn cars = 100(√3+1)

Answer 2

in∆ABD,

angle B=90°

angle C=45°

angle D=30°

in∆ABC,

Tan45°=ab/bc

1=100/bc

BC=100

IN∆ABD,

Tan30°=ab/bd

1/√3=100/bd

BD=100×√3

=100×1.73

=173

CD= distance between two cars

CD=bd-bv

=173-100

=73