Question

From the top of a tower 60 m tall, a body is thrown vertically down with a velocity of 10 m/s. At the same time, another body is thrown vertically upward from the ground with a velocity of 20 m/s. At what height above the ground do they meet? [take g = 10m/s²] (1) 20 m (3) 30 m (2) 40 m (4) 10 m​

Answer 1

Answer:

300 m

Explanation:

The initial velocity of the ball is =20 m/s.

The final velocity of the ball is =80 m/s.

The acceleration due to gravity is =10 m/s  

2

.

So, the height of the tower can be obtained from the expression:

v  

2

=u  

2

+2gh

Substitute the values in above expression:

80  

2

=20  

2

+(2×10×h)

h=  

20

6400−400

​

 m

h=  

20

6000

​

⇒300 m

Answer 2

Answer is 30m

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