Question

from the top of a tower a body is projected vertically up with a velocity of 4.9 MS the time after which it will pass through the point of projection is​

Answer 1

the required answer is 1second

KINDLY MARK AS BRAINLIEST

Answer 2

Given:

The initial velocity of the object = 4.9m/s

To find:

The time after which it will reach the point of projection.

Solution:

According to the First equation of Newton's law of motion,

V = u + at

Here,

V is the final velocity,

u is the initial velocity,

a is the acceleration,

t is the time taken.

Now, as our object reaches the maximum height the velocity becomes zero and then returns down.

So, the final velocity of the body is zero.

Also, it is thrown vertically upward so only gravitational acceleration will be against the motion.

Now, putting all the above values in the above equation, we get,

v = u + at

0 = 4.9 -9.8t

t = 0.5 sec.

Now, this time taken is to reach maximum height. To return to the original position again 0.5 sec will be required.

So the total time taken is 0.5 + 0.5 = 1 sec.

Hence, the time taken by the object to return to the original position is 1 second.