Question

From the top of a tower, a particle is
projected upwards and it reaches the
ground after 5 s. The initial velocity of the
particle is 12 m/s, the height of the tower is
(A) 55 m
(B) 65 m
(C) 75 m
(D) 85 m​

Answer 1

Please refer to the attachment for the solution

Answer 2

Answer:65m

Explanation:

By second equation of motion..

u=12ms~¹

t=5sec

g= -10ms~²

s = -h meters

S=ut+½at²

-h =12×5+½(-10) (5)²

-h = 60-125

-h = -65

h = 65m

It's the shortest and correct method....

Hope it helps...