Physics, asked by neerajcgn, 9 months ago

From the top of a tower a stone is thrown up which reaches the ground in time. t1. A second stone thrown down with the same speed reaches the ground in a time t2. A third stone released from rest from the same location reaches the ground in a time t3. then relation between them..... plz explain

Answers

Answered by nehachannaiah24
0

Explanation:

\sqrt{t1 t2 t3}  

- h = ut1 - 1/2 at^2

h= ut2  +1/2 at ^2

h= ut3 + 1/2 at ^2

if we multiply these three equations we get

h ( t1+ t2 + t3 ) = 1/2 = 1/2 gt1t2t3 ( t1 +t2+ t3)

and thus solving this will give us the above realtion

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