Question

From the top of a tower, the angles of depression of two objects on the same side of the tower are found to be alpha and beta (alpha>beta). If the distance between the object is p metres, show, show that the height h of the tower is given by h= p×tan× aplha × tan×beta divided by tan×alha+tan×beta. If alpha=60 degree; beta=30 degree; p=70metre; find the height of the tower.

Answer 1

Let AB be the tower of height h metres and C and D are two objects which are p metres apart.
Then........⬇

Answer 2

here is your answer above.