Question

From the top of an electric post, two wires are stretched to either side and fixed to the ground, 25 m apart. The wires make angles 60° and 45° with the ground. What is the height of the post?​

Answer 1

Answer:

9.25m

Step-by-step explanation:

Let the height of the post be x metre and distance between post and one of the wire fixed point be y metre.

In right Δ ADC,

AD = y m and CD = x m

CD = tan 55° × y

⇒ x = tan 55° × y

(From table, tan 55° = 1.428 = 1.43)

⇒ x = 1.43 × y …(i)

In right Δ CDB,

BD = AB – AD = (25 –y) m and CD = x

CD = tan 40° × BD

⇒ CD = tan 40° × (25 – y)

(From table, tan 40° = 0.839 = 0.84)

⇒ x = tan 40° × (25 – y)

⇒ x = 0.84 × (25 – y) …(ii)

Dividing eq. (i) from eq. (ii)

⇒ 0.84(25) – 0.84(y) = 1.43(y)

⇒ 1.43(y) + 0.84(y) = 0.84(25)

⇒ 2.27 (y) = 21

⇒ y = 9.25 m

Substituting value of y in eq. (i)

⇒ x = (1.43 × 9.25) m = 13.2275 m

Height of post is 9.25 m

Answer 2

Answer:

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