From the top of the building of height 60m. An observer find a car at angle of depression of 30°.find how for the car is from the building.(√3=1.73)
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[HeY Mate]
Given
- Height of building (AM) = 60m
- Angle of depression (Θ) = 30°
To Find
- Distance between car and building (MN)
Solution
Now,
Distance between car and building = base = 103.8m
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From the top of the building of height 60m. An observer find a car at angle of depression of 30°.find how for the car is from the building.(√3=1.73)
- Height of building (AB) = 60m
- Angle of depression = 30°
- Distance between car and building (BC)
Base = Distance btw care and building(BC) = 103.8m
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