Math, asked by mh12kn00, 8 months ago

From the top of the building of height 60m. An observer find a car at angle of depression of 30°.find how for the car is from the building.(√3=1.73)​

Answers

Answered by Skyllen
1

[HeY Mate]

\huge\bold\red{Answer}

Given

  • Height of building (AM) = 60m
  • Angle of depression (Θ) = 30°

To Find

  • Distance between car and building (MN)

Solution

 \tt \implies \: tan 30 =  \frac{perpendicular}{base}  \\   \tt \implies \:  \frac{1}{ \sqrt{3} }  =  \frac{60}{ base }  \\  \tt \implies base \:  = 60 \times  \sqrt{3}  \\ \tt \implies \: base = 60 \times 1.73 \\ \tt \implies \: base = 103.8m \\  \\

Now,

Distance between car and building = base = 103.8m

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I Hope It Helps You✌️

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Answered by InfiniteSoul
1

{\huge{\bold{\pink{\bigstar{\boxed{\bf{Question}}}}}}}

From the top of the building of height 60m. An observer find a car at angle of depression of 30°.find how for the car is from the building.(√3=1.73)

{\huge{\bold{\pink{\bigstar{\boxed{\bf{AnswEr}}}}}}}

{\bold{\blue{\boxed{\bf{GivEn}}}}}

  • Height of building (AB) = 60m
  • Angle of depression = 30°

{\bold{\blue{\boxed{\bf{To\: find:-}}}}}

  • Distance between car and building (BC)

{\bold{\blue{\boxed{\bf{solution}}}}}

\: tan 30 =  \dfrac{perpendicular}{base}

\:  \dfrac{1}{ \sqrt{3} }  =  \dfrac{60}{ base }

base \:  = 60 \times  \sqrt{3}

\: base = 60 \times 1.73

 \: base = 103.8m

Base = Distance btw care and building(BC) = 103.8m

_________________________❤

THANK YOU ❤

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