Question

From the top of tower 40m high, a projectile is thrown up with a velocity of 10 m/s, at an angle 45° with the horizontal. The horizontal distance where projectile strikes the ground.​

Answer 1

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>>From the top of tower 40 m high, a proje

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From the top of tower 40 m high, a projectile is thrown up with a velocity of 10

2

m/s, at an angle 45

o

with the horizontal

The time taken by it to reach the ground

Hard

Solution

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Correct option is A)

Initial velocity of projectile at 45

∘

with the horizontal =u=10

2

m/s

Vertical component of velocity ⇒u

y

⇒u

y

=10 m/s

Height of tower =40 m

Eq

n

of motion ⇒S=ut+

2

1

at

2

⇒−40=10t−

2

1

×10t

2

[g=10 m/s

2

].

⇒−40=10t−5t

2

⇒5t

2

−10t−40=0

⇒t

2

−2t−8=0

⇒(t+2)(t−4)=0

⇒t=−2 and t=4s

Answer 2

Answer:

Whenever light falls on the transition element compounds electrons excite and electrons absorb energy and excite. When these electrons de-excite they release visible light wavelength. That's why transition element compounds exhibit colour.